# WAEC Further Mathematics Obj And Essay/Theory Solution Questions and Answer – MAY/JUNE 2018 Expo Runz - 042tvseries

WAEC Further Mathematics Obj And Essay/Theory Solution Questions and Answer – MAY/JUNE 2018 Expo Runz.

**F/Maths OBJ:**

**1BCADDDDDBB**

**11DBABCCDDCC**

**21BCABBAABAB**

**31CBADBDDCAB**

**15a)**

(2.2) + 80(0.6) = 300(1.2) + 100 (3)

2.2B + 48 = 360 + 300

2.B + 48 = 660

2.2B = 660 - 48

2.2B = 612

Reation at B = 278.18N

Taking moment about B

80(2.1) + 300(1) = 2.2A + 100 (0.8)

224 + 300 = 2.3A + 80

524 - 80 = 2.2A

A = 444/2.2

Raction a+ A = 201.82N

CLICK HERE FOR THE DIAGRAM

15b)

CLICK HERE FOR THE DIAGRAM

(2.2) + 80(0.6) = 300(1.2) + 100 (3)

2.2B + 48 = 360 + 300

2.B + 48 = 660

2.2B = 660 - 48

2.2B = 612

Reation at B = 278.18N

Taking moment about B

80(2.1) + 300(1) = 2.2A + 100 (0.8)

224 + 300 = 2.3A + 80

524 - 80 = 2.2A

A = 444/2.2

Raction a+ A = 201.82N

CLICK HERE FOR THE DIAGRAM

15b)

CLICK HERE FOR THE DIAGRAM

12)

TABULATE

No of head|x 0|12|3|45|6|7|8|9|10

Frequency|f|2|7|23|36|11|61|100|12|8|5|3

Fx| 0|7|46|108|44|305|600|84|64|45|30

Ef = 268 Efx = 1333

(a) mean no heads = Efx/Ef = 1333/268 = 4.97

(b) prob (even no heads) = 23/268 + 11/268 + 100/268 + 8/268 + 3/268

= 145/268

(c) prob (odd as heads) 7/268 + 26/268 + 61/268 + 12/268 + 5/268

= 121/268

12)

TABULATE

No of head|x 0|12|3|45|6|7|8|9|10

Frequency|f|2|7|23|36|11|61|100|12|8|5|3

Fx| 0|7|46|108|44|305|600|84|64|45|30

Ef = 268 Efx = 1333

(a) mean no heads = Efx/Ef = 1333/268 = 4.97

(b) prob (even no heads) = 23/268 + 11/268 + 100/268 + 8/268 + 3/268

= 145/268

(c) prob (odd as heads) 7/268 + 26/268 + 61/268 + 12/268 + 5/268

= 121/268

9)

Draw the pie chart diagram

radius is the same hence

(y - 2)² + (X - 3)² = (y + 4)² + (X - 5)² = (y + 1)² + (X + 2)²

Taking the first pair

Y² - 4y + 4 + x² - 6x + 9 = y² + 8y + 16 + x² - 10x + 25

- 6x - 4y + 13 = -10x+8y+41

4x - 12y = 28

X = 3y = 7--------(1)

Taking the second pair

Y² + 3y + 16+x² - 10x+25 = y²+ 2y + 1 + x²+ 4x + 4

-10x + 3y + 41 = 4x + 2y + 5

14x - 6y = 36

7x - 3y = 18---------(2)

Eqn 2 minus Eqn 1

6x = 11

X = 11/6

Put this into Eqn (1)

11/6 - 3y = 7

3y = 11/6 - 7

3y = 11 - 42/6

3y = -31/6

y = -31/18

(a) coordinates of centre is (11/6, -31/18)

(b) Radius r = √(y-2)²+(x-3)²

r = √-31/18 -2)² + 11/6 - 3)²

r= √13.85 + 1.36

r = 3.9

(c) (X - 11/6)² + (y + 31/18)² = 3.9²

(X - 11/16)² + (y + 31/18)² = 15.21

9)

Draw the pie chart diagram

radius is the same hence

(y - 2)² + (X - 3)² = (y + 4)² + (X - 5)² = (y + 1)² + (X + 2)²

Taking the first pair

Y² - 4y + 4 + x² - 6x + 9 = y² + 8y + 16 + x² - 10x + 25

- 6x - 4y + 13 = -10x+8y+41

4x - 12y = 28

X = 3y = 7--------(1)

Taking the second pair

Y² + 3y + 16+x² - 10x+25 = y²+ 2y + 1 + x²+ 4x + 4

-10x + 3y + 41 = 4x + 2y + 5

14x - 6y = 36

7x - 3y = 18---------(2)

Eqn 2 minus Eqn 1

6x = 11

X = 11/6

Put this into Eqn (1)

11/6 - 3y = 7

3y = 11/6 - 7

3y = 11 - 42/6

3y = -31/6

y = -31/18

(a) coordinates of centre is (11/6, -31/18)

(b) Radius r = √(y-2)²+(x-3)²

r = √-31/18 -2)² + 11/6 - 3)²

r= √13.85 + 1.36

r = 3.9

(c) (X - 11/6)² + (y + 31/18)² = 3.9²

(X - 11/16)² + (y + 31/18)² = 15.21

2)

Log 3x - 3logx³+ 2 = 0

Log 3x - 3log3³/log3x + 2 = 0

Log3x - 3/log3x + 2 = 0

P - 3/p + 2 = 0 where P = log3x

P² - 3 + 2p = 0

P² + 2p - 3 = 0

(p + 3) ( p - 1) = 0

P = -3 OR p = 1

But log3x = p

when p = -3

Log3x = -3

X = 3-³ = 1/27

And when P = 1

Log3x = 1

X = 3¹ = 3

And X = 1/27 OR 3

2)

Log 3x - 3logx³+ 2 = 0

Log 3x - 3log3³/log3x + 2 = 0

Log3x - 3/log3x + 2 = 0

P - 3/p + 2 = 0 where P = log3x

P² - 3 + 2p = 0

P² + 2p - 3 = 0

(p + 3) ( p - 1) = 0

P = -3 OR p = 1

But log3x = p

when p = -3

Log3x = -3

X = 3-³ = 1/27

And when P = 1

Log3x = 1

X = 3¹ = 3

And X = 1/27 OR 3

3a)

U=x-2 hence x=u+2

therefore

x^2+5/(x-2)^4

=(u+2)^3+5/(u+2-2)^2

=(u+2)^3+5/u^4

3b)

(u+2)^3+5/u^4

=(u+2)^3/u^4+5/u^4

3a)

U=x-2 hence x=u+2

therefore

x^2+5/(x-2)^4

=(u+2)^3+5/(u+2-2)^2

=(u+2)^3+5/u^4

3b)

(u+2)^3+5/u^4

=(u+2)^3/u^4+5/u^4

4)

sn=n/2[2a+(n-1)d]

s12=12/2[2a+11d]

s12=6(2a+11d]=168

2a+11d=28 eq-----(1)

multipply 1by2 to obtain

2a+4d=14 eq------(3)

subtract (3)from(2)

7d=14

d=2

sub for d in (1)

a+4=7

a+7-4-3

a=3

common difference d=2

first term a=3

4)

sn=n/2[2a+(n-1)d]

s12=12/2[2a+11d]

s12=6(2a+11d]=168

2a+11d=28 eq-----(1)

multipply 1by2 to obtain

2a+4d=14 eq------(3)

subtract (3)from(2)

7d=14

d=2

sub for d in (1)

a+4=7

a+7-4-3

a=3

common difference d=2

first term a=3

5)

tabulate

X,y,d,d^2

A 8,6,2,4

B 5,3,2,4

C 1,4,-3,9

D 7,8,-1,1

E 2,5,-3,9

F 6,7,-1,1

G 3,1,2,4

H 4,2,2,4

Ed^2 =4+4+9+1+9+1+4+4

=36

r=1-6£d^2/n(n^2-1)

=1-6*36/8(8^2-1)=1-216/504

=1-0.43

=0.57

5)

tabulate

X,y,d,d^2

A 8,6,2,4

B 5,3,2,4

C 1,4,-3,9

D 7,8,-1,1

E 2,5,-3,9

F 6,7,-1,1

G 3,1,2,4

H 4,2,2,4

Ed^2 =4+4+9+1+9+1+4+4

=36

r=1-6£d^2/n(n^2-1)

=1-6*36/8(8^2-1)=1-216/504

=1-0.43

=0.57

1)

X-3(12-2x+8)+4(30-5x-4)+3(-20-4)=24

X-3(20-2x)+4(26-5x)+3(-24)= -24

20x-2x^2+60+6z+104-20x-72=24

20x^2+6x-60+104-72+24=0

-2x^2+6x-4=0

Divide 2x by -2

x2^2-3x+2=0

x2^2-2x-x+2=0

x(x-2)-1(x-2)-0

(x-1)(x-2)=0

x-1 or x=2

1)

X-3(12-2x+8)+4(30-5x-4)+3(-20-4)=24

X-3(20-2x)+4(26-5x)+3(-24)= -24

20x-2x^2+60+6z+104-20x-72=24

20x^2+6x-60+104-72+24=0

-2x^2+6x-4=0

Divide 2x by -2

x2^2-3x+2=0

x2^2-2x-x+2=0

x(x-2)-1(x-2)-0

(x-1)(x-2)=0

x-1 or x=2

6)

It follow that:

P(n) = 1/3 and p(k)¹ = 1 - 1/3 = 2/3

P(T) = 1/5 and P(T)¹ = 1- 1/5 = 4/5

Hence, probability that only one if the them will be solve the questions will be:

= (1/3 × 4/5) + (1/5 × 2/3)

= 4/15 + 2/15

= 6/15

= 2/5

6)

It follow that:

P(n) = 1/3 and p(k)¹ = 1 - 1/3 = 2/3

P(T) = 1/5 and P(T)¹ = 1- 1/5 = 4/5

Hence, probability that only one if the them will be solve the questions will be:

= (1/3 × 4/5) + (1/5 × 2/3)

= 4/15 + 2/15

= 6/15

= 2/5

8a)

m1 = 20kg

u1 = 8ms-1

m2 = 30kg

u2 = 50ms-1

(a) in same direction

m1u1 + m2u2 = (m1+m2)v

20 × 80 + 30 × 50 = (20+30)v

1600+1500 = 50v

3100/50 = 50/50

V = 62ms-1

8b)

M1=20kg

u1=80mls

m2=30kg

u2=50mls

v=?

M1u1+m2u2=v(m1+m2)

(20*80)+(30*(-50))=v(20+30)

1600-1500=50v

100=50v

v=100/50

v=2mls

8a)

m1 = 20kg

u1 = 8ms-1

m2 = 30kg

u2 = 50ms-1

(a) in same direction

m1u1 + m2u2 = (m1+m2)v

20 × 80 + 30 × 50 = (20+30)v

1600+1500 = 50v

3100/50 = 50/50

V = 62ms-1

8b)

M1=20kg

u1=80mls

m2=30kg

u2=50mls

v=?

M1u1+m2u2=v(m1+m2)

(20*80)+(30*(-50))=v(20+30)

1600-1500=50v

100=50v

v=100/50

v=2mls

7)

m = 3i - 2j ; n = 2i + 3j ; p = i + 6j

Therefore:

4(3i - 2j) +2(2i +3j) -3(-i + 6j)

12i - 8j + 4i + 6j + 3i - 18j

12i + 4i + 3i - 8j + 6j - 18j

19i = 20j

7)

m = 3i - 2j ; n = 2i + 3j ; p = i + 6j

Therefore:

4(3i - 2j) +2(2i +3j) -3(-i + 6j)

12i - 8j + 4i + 6j + 3i - 18j

12i + 4i + 3i - 8j + 6j - 18j

19i = 20j

*–*

*Do not call us just text message, we will reply to your message immediately**-Know the difference between password link/online answer and direct mobile*

=========================

*042tvseries.Com send all exam expo answer earlier than others*
============================

*WAEC ssce 2018 Further Mathematics expo answers, Ssce 2018 Further Mathematics objective and essay Expo answers now available, may/june Further Mathematics theory Answers for 2018, Further Mathematics obj and theory Questions WAEC Ssce Expo Answers Here, Free wassce Further Mathematics objective, essay & theory correct Expo 2018 answers Runz WAEC Further Mathematics, WAEC Ssce 2018 Free Further Mathematics essay, obj and theory Questions and Answers Expo for WAEC Further Mathematics Paper 1 and Paper 2 objective and essay Questions and Answers Expo Now Posted, Free Further Mathematics objective ans for internal ssce, see WAEC ssce expo Further Mathematics obj and theory, essay questions for free, loadedexpo correct wassce Further Mathematics ans, sure WAEC ssce Further Mathematics objective answers runz runs expo free real and correct WAEC ssce 2018 may/june Further Mathematics free expo runz runs ans answers online for free see free answers online, 2018 Verified WAEC Free Ssce Further Mathematics Obj and theory Answers have been posted REAL WAEC SSCE Further Mathematics QUESTIONS & ANSWERS Direct To Phone Number AS Text message, RE: 2018 WASSCE Further Mathematics (Expo) WAEC 2018 certified runs Further Mathematics questions and answers WAEC SSCE November/December 2018 Further Mathematics THEORY / ESSAY / OBJ QUESTION AND EXPO I need WAEC ssce free expo site, how can I get WAEC Further Mathematics answer for free, WAEC 2018 Further Mathematics essay, Objective And Theory Question and Answer Now Posted, Real 2018/2019 may/june wassce WAEC Further Mathematics objective, essay and theory 100% correct expo questions and answers runz chokes runs, verified 2018 WAEC Further Mathematics theory, essay and obj WAEC Further Mathematics expo website, WAEC ssce Further Mathematics live cheats, sure November/December WAEC SSCE 2018 Further Mathematics original objective, theory and essay questions and answer now available here, 100% WAEC ssce Further Mathematics expo, 2018 wassce Further Mathematics obj, essay and theory runz now posted, correct WAEC ssce Further Mathematics objective, essay (theory) answer now ready, free 2018 wassce Further Mathematics obj, theory and essay best expo site WAEC ssce Further Mathematics questions and answers, password for certified WAEC ssce Further Mathematics essay theory obj expo, how to get/ where to get wassce Further Mathematics theory, essay and objective expo answer direct to my phone as text message, trusted WAEC ssce Further Mathematics questions and answer, i need WAEC Ssce may/june Further Mathematics essay theory objective obj Expo 2018 answers on whatsapp, gidifans Further Mathematics answer, solutionclass Further Mathematics answer, 042tvseries Further Mathematics answer, codedexam WAEC Further Mathematics answer, wapbaze Further Mathematics answer, wapextra Further Mathematics expo, Martinlibrary Further Mathematics expo, examgists WAEC Further Mathematics expo, WAEC Further Mathematics objectives answer, naija WAEC Further Mathematics expo free answer*

Real and Confirmed WAEC Further Mathematics Questions and Expo Answer – May/June 2018

Verified WAEC 2018 May/June Further Mathematics OBJ and Essay Answer and Solution to the questions.

**GOODLUCK!!!**

## No comments:

After dropping your comment, keep calm, it may take minutes before it appears after moderation.

Your comment(s) are appreciated.

You want to get notified when i reply your comment? Kindly tick the Notify Me box.